Yes, the 9th power of any number always ends with the same digit as the initial number.
The same is true for the 5th power and the 13th power and 17th power…ie every 4th increase in power starting with “1”
There are repetitive endings for most (if not all) powers eg if the initial number “n” ends in 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 then the last digit of n^2 will be 0, 1, 4, 9, 6, 5, 6, 9,4 ,1 etc and the last digits of n^(2+4) will also end in 0, 1, 4, 9, 6, 5, 6, 9,4 ,1
Now that Parliament has been suspended, I thought it might make a nice break to put politics to one side again, and give the old brains a rest for five weeks …
The diagram below shows a standard set of 28 dominoes. They have been set out in a neat pattern.
I have drawn in the edges of one domino, ie 6-4.
All you have to do is draw in the edges of the other 27 !
Mike ! You cannot be serious (as McEnroe once said !)
If you are serious, I will try to explain, and I will scan a copy of my list of the 28 dominoes that form the standard set. 6-6; 6-5; 6-4: … 5-5: 5-4: 5-3: … 1-1: 1-0: 0-0.